Как рассчитать mr в химии

Как рассчитать mr в химии

1. (Mr)

: (H2SO4)

1. .

H2SO4

2.

Mr (-) = Ar (.1) n1 + Ar (.2) n2 + Ar (.3) n3

3. ,

Mr(H2SO4 ) = Ar(H)2 + Ar(S)1 + Ar(O)4 = 12 + 32 + 16∙4=98

4. .

: Mr (H2SO4 ) = 98.

2.

: (IV) SO2.

1.

m(.1) : m(.2) = Ar(.1) n1 : Ar(.2) n2

2. ,

m(S): m(O) = 32: 16∙2=32 : 32

3. 32

m(S) : m(O) = 1:1

3.

: (III) Fe2O3.

1.

w () = Ar()∙n :Mr(-)

2. (III)

Mr (Fe2O3) = 56∙2+16∙3 = 160

3. , ,

w(Fe) = 56∙2:160 = 0,7(70%)

w() = 16∙3:160= 0,3 (30%)

4.

: , 40% 60 % . 80.

1.

n() = Mr(-)w /Ar()

n(S)=800,4/32 = 1

n()=800,6/16 = 3

2.

SO3

5.

: , , 24, 28 48 %.

1.

n1: n2: n3 = w(.1)/r(.1): w(.2)/r(.2): w(.3)/r(.3)

2. ,

n(S): n(Fe): n(O) = 24/32: 28/56: 48/16 =

0,75:0,5:3

3. 4

n(S): n(Fe): n(O) = 3:2:12

4.

S3Fe2O12 Fe2(S4)3

6.

: , , 18:7. .

1.

n1: n2 = m(.1)/r(.1): m(.2)/r(.2)

2.

n(Mg): n(N) = 18/24: 7/14 = 0,75:0,5

3. 4

n(Mg): n(N) = (0,75:0,5) 4 = 3:2

4.

Mg3N2

7.

: 8,316 26,4 CO2. 1,875 /. .

1.

= ρ V m

=1,875 /22, 4 / = 42 /

2.

w() = 12//44/ = 0,27

m() = m(2) w() = 26,4 0,27 =7,128

3.

m() = 8,316 -7,128 = 1,188

4.

n():n() = 7,128/12 /:1,188 /1 / = 0,594: 1,188 = 1:2, . , 2

5. ,

(2) = 14 /

x = 42/: 14/ =3

6. , . . 3 ,

:

36

.

1. :

) SO2

) 26

) CuSO4

. .2 3

2. , 75%.

. .5

3. , 70,9% 29,1% 110.

. .4

4. , , 3,2 2,24 .

. .6

:

1. :

— ;

— ;

— .

2. 2, 4 .31, 5,9 . 32



Источник: pandia.ru


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